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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

In a Young's double slit experiment, $I_{0}$ is the maximum intensity and $β$ is the fringe width. Intensity at point $P$ which is distance $x$ from central maxima is

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Answer:

Solution:

Path difference at point $P = \frac{x d}{D}$

$∴$ phase deff at. $P = \frac{2 π}{λ} \frac{x d}{D} = \frac{2 π x}{β}$

$∴$ Intensity at $P = I + I + 2 I \cos \frac{2 π x}{β}$

$= 2 I [1 + \cos \frac{2 π x}{β}] [∵ I_{0} = 4 I]$

$= 4 I \cos^{2} \frac{π x}{β} = I_{0} \cos^{2} \frac{π x}{β}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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