Two slits are separated by a distance of 0.5 mmand illuminated withlight of wavelength λ = 6000 A ˚ . If the screen is placed at 2.5 m from the slits. The distance of the third bright fringe from the centre will be

Distance of n th bright fringe from the centre, x n = d n D λ So, x 3 = 0.5 × 1 0 − 3 3 × 2.5 × 6000 × 1 0 − 10 = 9 × 1 0 − 3 m = 9 mm

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2017

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Two slits are separated by a distance of 0.5 mmand illuminated withlight of wavelength $λ = 6000 \overset{˚}{A}$ . If the screen is placed at $2.5 m$ from the slits. The distance of the third bright fringe from the centre will be

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Solution:

Distance of $n^{th}$ bright fringe from the centre, $x_{n} = \frac{n D λ}{d}$ So, $x_{3} = \frac{3 \times 2.5 \times 6000 \times 1 0 ^{- 10}}{0.5 \times 1 0 ^{- 3}} = 9 \times 1 0^{- 3} m = 9 mm$

Stream:AIIMSSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2017

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