In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 A ˚ , then wavelength of firs

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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 A ˚ , then wavelength of first maximum will be:

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In a single slit experiment, For diffraction maxima, a sin θ = ( 2 n + 1 2 A ˚ ​ and for diffraction minima, a sin θ = n λ According to question, ​ ( 2 × 1 + 1 2 λ ​ = 1 × 6600 ( ∵ λ R ​ = 6600 A ˚ ) λ = 3 6600 × 2 ​ λ = 4400 A ˚ ​

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