The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum of the minimum intensity in the interference pattern is:

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Since, Intensity ∝ width of slit ( ω ) ​ so, I 1 ​ = I , I 2 ​ = 4 I I m i n ​ = ( I 1 ​ ​ − I 2 ​ ​ ) 2 = I I m a x ​ = ( I 1 ​ ​ + I 2 ​ ​ ) 2 = 9 I I m i n ​ I m a x ​ ​ = I 9 I ​ = 1 9 ​ ​

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