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PhysicsWave OpticsYDSEMedium2 minPYQ_2019
PhysicsMediumsingle choice

In a Young's double-slit experiment, the ratio of the slit's width is 4 :1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be

Options:

Answer:
B
Solution:

Intensity  width of slit
I1I2=41.
ImaxImin=I1+I2I1-I22=I1I2+1I1I2-12 
=4+14-12=312=91
Imax :Imin=9:1

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
2mℹ️ Source: PYQ_2019

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