In a Young's double slit experiment with light of wavelength λ , fringe pattern on the screen has fringe width β . When two thin transparent glass (refractive index μ ) plates of thickness t 1

Question

In a Young's double slit experiment with light of wavelength $λ$ , fringe pattern on the screen has fringe width $β$ . When two thin transparent glass (refractive index $μ$ ) plates of thickness $t_{1}$ and $t_{2}$ $(t_{1} > t_{2})$ are placed in the path of the two beams respectively, the fringe pattern will shift by a distance

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Answer:

C

Solution:

$Shift = \frac{β ( μ - 1 )}{λ} t_{1} - \frac{β ( μ - 1 )}{λ} t_{2} = \frac{β ( μ - 1 )}{λ} (t_{1} - t_{2})$

TestHub · Accepted Answer

Shift ​ = λ β ( μ − 1 ) ​ t 1 ​ − λ β ( μ − 1 ) ​ t 2 ​ = λ β ( μ − 1 ) ​ ( t 1 ​ − t 2 ​ ) ​

Physics - Wave Optics Question with Solution | TestHub

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