In a Young's double slit experiment, a combination of two glass wedges A and B , having refractive indices 1.7 and 1.6, respectively, are placed in front of the slits, as shown in the figure. The

Question

In a Young's double slit experiment, a combination of two glass wedges $A$ and $B$ , having refractive indices 1.7 and 1.6, respectively, are placed in front of the slits, as shown in the figure. The separation between the slits is $d = 2 mm$ and the shortest distance between the slits and the screen is $D = 2 m$ . Thickness of the combination of the wedges is $t = 12 μ m$ . The value of $l$ as shown in the figure is 1 mm . Neglect any refraction effect at the slanted interface of the wedges. Due to the combination of the wedges, the central maximum shifts (in mm) with respect to O by $____$

TestHub · Accepted Answer

x + y = 12 μ m 12 4 ​ = x 1 ​ ⇒ x = 3 μ m , y = 9 μ m Setting the optical path difference at the shifted central maximum to zero gives Δ y = − 0.6 mm Required magnitude = 0.60 mm.

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