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PhysicsWave on StringMiscellaneousMedium2 minPYQ_2020

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Two identical strings $X$ and $Z$ made of same material have tension $T_{X}$ and $T_{Z}$ in then if their fundamental frequencies are $450 Hz$ and $300 Hz$ , respectively, then the ratio $T_{X} / T_{Z}$ is :

Options:

Answer:

A

Solution:

$\begin{array}{l} f_{X} = \frac{1}{2 ℓ} \sqrt{\frac{T_{X}}{μ}} \end{array}$

$\begin{array}{l} f_{Z} = \frac{1}{2 ℓ} \sqrt{\frac{T_{Z}}{μ}} \end{array}$

$\begin{array}{l} \frac{f_{X}}{f_{Z}} = \frac{450}{300} = \sqrt{\frac{T_{X}}{T_{Z}}} \end{array}$

$\Rightarrow T_{X} / T_{Z} = 9 / 4 = 2.25$

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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