Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringWavesHard2 minQB

PhysicsHardnumerical

The same steel wire (1 m, 0.1 kg, $1 0^{- 6}$ m²) is cooled by 40°C instead. Find the fundamental frequency. (answer in $Hz$ ).

Answer:

15.60

Solution:

$T = 2 \times 1 0^{11} \times 1 0^{- 6} \times 1.21 \times 1 0^{- 5} \times 40 = 96.8$ N. $v = 968 = 31.1$ m/s. $f = 15.6$ Hz.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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