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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringWavesMedium2 minQB

PhysicsMediumsingle choice

A 75 cm string fixed at both ends produces resonant frequencies 384 Hz and 288 Hz without there being any other resonant frequency between these two. Wave speed for the string is:

Options:

Answer:

Solution:

Successive harmonics differ by $f_{1} = v /2 L$ . $f_{1} = 384 - 288 = 96$ Hz. $v = 2 L f_{1} = 2 \times 0.75 \times 96 = 144$ m/s.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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