Start Free Mock LoginAlready registered? Login here

Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringWavesMedium2 minQB

PhysicsMediumsingle choice

A string of length 1.5 m with its two ends clamped is vibrating in fundamental mode. Amplitude at the centre of the string is 4 mm. The minimum distance between the two points having amplitude 2 mm is:

Options:

Answer:

Solution:

Amplitude is $4 sin (π x /1.5)$ mm. Setting it to 2 mm: $sin (π x /1.5) = \frac{1}{2}$ , so $x = 0.25$ m or $x = 1.25$ m. The two points are 1.0 m apart.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...