A string carries y = 0.01 sin ( 2 x + 40 t ) ( x , y in m, t in s) and has linear density 2 × 1 0 − 4 kg/m. Its tension in N is:

v = 40/2 = 20 m/s. T = μ v 2 = 2 × 1 0 − 4 × 400 = 0.08 N.

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A string carries $y = 0.01 sin (2 x + 40 t)$ ( $x$ , $y$ in m, $t$ in s) and has linear density $2 \times 1 0^{- 4}$ kg/m. Its tension in N is:

Answer:

Solution:

$v = 40/2 = 20$ m/s. $T = μ v^{2} = 2 \times 1 0^{- 4} \times 400 = 0.08$ N.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

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