Physics - Wave on String Question with Solution | TestHub

A wire of density $8\times 10^3\mathrm{kg}/{\mathrm{m}}^3$ is stretched between two clamps 0.5 m apart. The extension developed in the wire is $3.2\times 10^{-4}\mathrm{m}$. If $\mathrm{Y}=8\times 10^{10}\mathrm{N}/{\mathrm{m}}^2$, the fundamental frequency of vibration in the wire will be $\_\_\_\_$ Hz .