Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is a and the phase of A is ah

Question

Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is a and the phase of A is ahead by π /3 than that of B and the distance A P is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter:

TestHub · Accepted Answer

Path difference 0.5 m with λ = 1 m gives a phase lag of π for A at P . Net phase difference = π /3 − π = − 2 π /3 . A R ​ = 2 a cos ( Δ ϕ /2 ) = 2 a cos ( π /3 ) = a .

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