As shown in figure light string PQR is stretched by force F = ( 3 − 10 kt ) N , where k is a constant and t is time in second. At time t = 0 , a pulse is generated at the end P of the string. For what

Question

As shown in figure light string PQR is stretched by force $F = (3 - 10 kt) N$ , where k is a constant and t is time in second. At time $t = 0$ , a pulse is generated at the end P of the string. For what value of k (in $N / s$ ) the value of force becomes zero as the pulse reaches point Q . Given mass per unit length of string is $0.03 kg / m$ .

TestHub · Accepted Answer

For pulse dt dx ​ = μ T ​ ​ = μ 3 − 10 kt ​ ​ ⇒ ∫ 0 L ​ dx = ∫ 0 t 0 ​ ​ μ 3 − 10 kt ​ ​ dt And 3 − 10 kt o ​ = 0

Physics - Wave on String Question with Solution | TestHub

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