A string of length 2 L, obeying Hooke's Law, is stretched so that its extension is L. The speed of the transverse wave travelling on the string is v. The string is further stretched so that the e

Question

A string of length 2 L, obeying Hooke's Law, is stretched so that its extension is L. The speed of the transverse wave travelling on the string is v. The string is further stretched so that the extension in the string becomes 4L. The speed of transverse wave travelling on the string will be $x 2 v$ . Calculate the value of x .

Answer:

2

Solution:

$v = \frac{T}{μ}$ ; $T_{2} = 4 T_{1}$ (extension L to 4L) and $μ_{2} = \frac{μ _{1}}{2}$ (length doubles)

$v_{2} = v 4 \times 2 = 22 v$ , so x = 2

Answer 2

TestHub · Accepted Answer

v = μ T ​ ​ ; T 2 ​ = 4 T 1 ​ (extension L to 4L) and μ 2 ​ = 2 μ 1 ​ ​ (length doubles) v 2 ​ = v 4 × 2 ​ = 2 2 ​ v , so x = 2 Answer 2

Physics - Wave on String Question with Solution | TestHub

Doubts & Discussion