A TV signal has wavelength 3 m. The path difference between the direct and reflected rays changes at a steady 6 m/s as the plane moves. How often does the signal fade (time between successive fades), in s?
Answer:
0.50
Solution:
One fade cycle needs a path-difference change of $λ = 3$ m, so $T = 3/6 = 0.5$ s.

Question

A TV signal has wavelength 3 m. The path difference between the direct and reflected rays changes at a steady 6 m/s as the plane moves. How often does the signal fade (time between successive fades), in s?

Answer:

0.50

Solution:

One fade cycle needs a path-difference change of $λ = 3$ m, so $T = 3/6 = 0.5$ s.

TestHub · Accepted Answer

One fade cycle needs a path-difference change of λ = 3 m, so T = 3/6 = 0.5 s.

Physics - Wave on String Question with Solution | TestHub

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