Physics - Wave on String Question with Solution | TestHub

A sonometer wire is fixed at both ends.

For a string fixed at both ends, the $p$-th overtone corresponds to the $(p+1)$-th harmonic.

The third overtone corresponds to the $4$-th harmonic.

In the $4$-th harmonic, the wire vibrates in $4$ loops.

Each loop contains one antinode, so the number of antinodes is $4$.

The number of nodes is one more than the number of loops, which is $4+1=5$.

Thus, there are $5$ nodes and $4$ antinodes.

Answer: 5 nodes and 4 antinodes