Physics - Wave on String Question with Solution | TestHub

The given equation of the stationary wave is $y=12\cos \left(\frac{\pi x}{10}\right)\sin (36\pi t)$ cm.

Comparing this with the standard equation of a stationary wave $y=A\cos (kx)\sin (\omega t)$, we get:

$k=\frac{\pi }{10}$

Since $k=\frac{2\pi }{\lambda }$, we have:

$\frac{2\pi }{\lambda }=\frac{\pi }{10}$

$\lambda =20$ cm

The distance between a node and the successive antinode is given by $\frac{\lambda }{4}$.

Distance $=\frac{20}{4}=5$ cm.