Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringStandingEasy2 minPYQ_2023
PhysicsEasynumerical

A string of length1 mand mass2×10−5 kgis under tensionT. When the string vibrates, two successive harmonics are found to occur at frequencies750 Hzand1000 Hz. The value of tensionTis _____ newton.

Answer:
5.00
Solution:

Given: l=1 m, m=2×10–5 kg.

As successive harmonics are being given, so it is the case of both ends fixed.

Now,

fn+1-fn=1000-750

⇒n+12lTμ-n2lTμ=250

⇒12lTμ=250

⇒T2×10-5=250×2×1

⇒T2×10-5=25×104

⇒T=50×10-1

⇒T=5 N

Stream:JEE_ADVSubject:PhysicsTopic:Wave on StringSubtopic:Standing
⏱ 2mℹ️ Source: PYQ_2023

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