Physics - Wave on String Question with Solution | TestHub

The distance between two consecutive nodes in a standing wave is $\frac{\lambda }{2}$.

Given that the node separation is $5\text{cm}$, we have:

$\frac{\lambda }{2}=5\text{cm}=0.05\text{m}$

$\lambda =0.1\text{m}$

The velocity of the wave is given as $v=2\text{m/s}$.

The frequency of vibration $f$ is related to the wave velocity and wavelength by the formula:

$f=\frac{v}{\lambda }$

Substituting the values:

$f=\frac{2}{0.1}=20\text{Hz}$

Answer: $20\text{Hz}$