For the stationary wave y = 4 sin ( 15 π x ) cos ( 96 π t ) the distance between a node and the next antinode is

On comparing given equation with standard equation, we get ⇒ λ 2 π = 15 π ⇒ λ = 30 Distance between the node and antinode = 4 λ = 4 30 = 7.5

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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringStandingEasy2 minPYQ_2011

PhysicsEasysingle choice

For the stationary wave $y = 4 sin (\frac{π x}{15}) cos (96 π t)$ the distance between a node and the next antinode is

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Solution:

On comparing given equation with standard equation, we get $\Rightarrow \frac{2 π}{λ} = \frac{π}{15} \Rightarrow λ = 30$ Distance between the node and antinode $= \frac{λ}{4}$ $= \frac{30}{4} = 7.5$

Stream:MHT_CETSubject:PhysicsTopic:Wave on StringSubtopic:Standing

⏱ 2mℹ️ Source: PYQ_2011

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