Physics - Wave on String Question with Solution | TestHub

Phase difference $\Delta \varphi =60^{\circ }=\frac{\pi }{3}$ rad

Path difference $\Delta x=0.6$ m

Frequency $f=500$ Hz

Using the relation between phase difference and path difference:

$\Delta \varphi =\frac{2\pi }{\lambda }\Delta x$

$\frac{\pi }{3}=\frac{2\pi }{\lambda }\times 0.6$

$\lambda =6\times 0.6=3.6$ m

The velocity of the wave is given by:

$v=f\lambda$

$v=500\times 3.6=1800$ m/s

$v=1.8$ km/s

Answer: $1.8\mathrm{km}/\mathrm{s}$