Physics - Wave on String Question with Solution | TestHub

The given wave equations are:

$y_1=a\sin (\omega t+kx+0.57)$

$y_2=a\cos (\omega t+kx)$

Expressing the second wave in terms of sine:

$y_2=a\sin \left(\omega t+kx+\frac{\pi }{2}\right)$

The phase difference $\Delta \varphi$ between the two waves is:

$\Delta \varphi =\left(\omega t+kx+\frac{\pi }{2}\right)-(\omega t+kx+0.57)$

$\Delta \varphi =\frac{\pi }{2}-0.57$

Substituting $\pi =3.14$:

$\Delta \varphi =\frac{3.14}{2}-0.57=1.57-0.57=1.0$ radian

Answer: $1.0$ radian