Physics - Wave on String Question with Solution | TestHub

We know. Frequency is ratio of velocity of sound and wavelength: $f=\frac{v}{\lambda }$ For tube of length , in fundamental mode wavelength is given by $\frac{\lambda }{2}=L$ $\frac{\lambda }{2}=L$. $\therefore f=\frac{v}{2L}$ Now, if tube is dipped one third, then for fundamental mode in air column has: $\begin{array}{rl}& \frac{{\lambda }^{\prime }}{2}=\left(\frac{2}{3}L\right)\\ & \therefore f^{\prime }=\frac{3v}{4L}=\frac{3}{2}f\end{array}$