Physics - Wave on String Question with Solution | TestHub

The general wave equation is $y=A\sin (kx\pm \omega t)$.

Given $A=0.02$ m.

Wavelength $\lambda =\frac{4m}{5waves}=0.8$ m.

Wave number $k=\frac{2\pi }{\lambda }=\frac{2\pi }{0.8}=7.85$ rad/m.

Angular frequency $\omega =vk=128\times 7.85=1005$ rad/s.

Since the wave travels in the +ve x-direction, the sign is negative.

Thus, $y=(0.02)\sin (7.85x-1005t)$.