Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringMiscellaneousMedium2 minPYQ_2022

PhysicsMediumsingle choice

The fundamental frequency of a wire stretched by $2 kgwt$ is $100 Hz$ . The weight required to produce its octave is

Options:

Answer:

Solution:

Octave means the new frequency is $2 n$ The velocity of sound is proportional to the square-root of the tension in the wire. The frequency is directly proportional to the velocity of sound in the wire: $∴ n \propto T \Rightarrow \frac{n _{2}}{n _{1}} = \frac{T _{2}}{T _{1}} ∴ T_{2} = T_{1} [\frac{n _{2}^{2}}{n _{1}^{2}}] = 4 T_{1} = 8 kgwt$

Stream:MHT_CETSubject:PhysicsTopic:Wave on StringSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...