Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringWavesMedium2 minQB

PhysicsMediumsingle choice

A wire of linear density $0.01$ kg/m under 400 N tension resonates at 250 Hz and the next higher resonance is 300 Hz. Its length in metres is:

Answer:

Solution:

$v = 400/0.01 = 200$ m/s. $Δ f = v /2 L = 50$ Hz, so $L = 200/100 = 2$ m.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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