A sound wave is travelling with a frequency of 50 Hz . The phase difference between the two points in the path of a wave is 3 π . The distance between those two points is (Velocity of sound in air = 330 m / s )

Phase difference ϕ = λ 2 π x λ = f v = 50 330 = 6.6 m ∴ x = 2 π λ ϕ = 2 π 6.6 × 3 π = 6 6.6 = 1.1 m

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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringEquation/graphMedium2 minPYQ_2021

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A sound wave is travelling with a frequency of $50 Hz$ . The phase difference between the two points in the path of a wave is $\frac{π}{3}$ . The distance between those two points is (Velocity of sound in air $= 330 m / s)$

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Phase difference $ϕ = \frac{2 π}{λ} x$ $λ = \frac{v}{f} = \frac{330}{50} = 6.6 m ∴ x = \frac{λ ϕ}{2 π} = \frac{6.6}{2 π} \times \frac{π}{3} = \frac{6.6}{6} = 1.1 m$

Stream:MHT_CETSubject:PhysicsTopic:Wave on StringSubtopic:Equation/graph

⏱ 2mℹ️ Source: PYQ_2021

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