The equation of vibration of a stretched string fixed at both ends and vibrating in 5 th harmonic is Y = 3 sin ( 0 ⋅ 4 x ) cos ( 200 π t ) where 'x' and 'Y' are in cm and t in second. Length of the string is

For 5 th harmonic, the string of length L vibrates in 5 loops 2 5 λ = L Now λ 2 π = 0.4 ∴ λ = 0.4 2 π = 4 20 π = 5 π ∴ L = 2 5 × 5 π = 2 25 π = 12.5 π

Start Free Mock LoginAlready registered? Login here

Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringMiscellaneousMedium2 minPYQ_2020

PhysicsMediumsingle choice

The equation of vibration of a stretched string fixed at both ends and vibrating in $5^{th}$ harmonic is $Y = 3 sin (0 \cdot 4 x) cos (200 π t)$ where 'x' and 'Y' are in $cm$ and $t$ in second. Length of the string is

Options:

Answer:

Solution:

For $5^{th}$ harmonic, the string of length $L$ vibrates in 5 loops $\frac{5 λ}{2} = L$ Now $\frac{2 π}{λ} = 0.4 ∴ λ = \frac{2 π}{0.4} = \frac{20 π}{4} = 5 π$ $∴ L = \frac{5 \times 5 π}{2} = \frac{25 π}{2} = 12.5 π$

Stream:MHT_CETSubject:PhysicsTopic:Wave on StringSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...