A simple harmonic progressive wave is given by Y = Y 0 sin 2 π ( nt − λ x ) . If the wave velocity is ( 8 1 ) th the maximum particle velocity, then the wavelength is

Maximum particle velocity = Y 0 ω = 2 π n Y 0 Wave velocity = n λ ∴ 8 2 π n Y 0 = n λ ∴ λ = 4 π Y 0

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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringEquation/graphEasy2 minPYQ_2021

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A simple harmonic progressive wave is given by $Y = Y_{0} sin 2 π$ $(nt - \frac{x}{λ})$ . If the wave velocity is $(\frac{1}{8})^{th}$ the maximum particle velocity, then the wavelength is

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$Maximum particle velocity = Y_{0} ω = 2 π n Y_{0} Wave velocity = n λ ∴ \frac{2 π n Y _{0}}{8} = n λ ∴ λ = \frac{π Y _{0}}{4}$

Stream:MHT_CETSubject:PhysicsTopic:Wave on StringSubtopic:Equation/graph

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