Physics - Wave on String Question with Solution | TestHub

For p number of loops in stretched string, the length is given by
$l=\frac{p\lambda }{2}$… (i)
As, number of harmonics = number of loops = number of anti-nodes = p …. (ii)
Also, number of nodes = number of anti-nodes + 1
Here, number of nodes = m
Number of anti-nodes = m-1 from Eq. (ii)
$p=m-1$
Putting this value of p in Eq. (i), we get
$l=\frac{\left(m-1\right)\lambda }{2}$