Physics - Wave on String Question with Solution | TestHub

Frequency of vibration of sonometer wire is given as

$n=\frac{1}{2l}\sqrt{\frac{T}{m}}=\frac{1}{2l}\sqrt{\frac{T}{\pi r^{2}d}}$

$\Rightarrow n\propto \frac{1}{\sqrt{d}}$$n\propto \frac{1}{r}\mathrm{a}\mathrm{n}\mathrm{d}\mathrm{ }\mathrm{n}\mathrm{ }\propto \frac{1}{l}$

If the length and diameter of the wire are doubled.

The new frequency will be$\frac{n}{4}$.