Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringEquation/graphEasy2 minPYQ_2020

PhysicsEasysingle choice

Two strings of copper are stretched to the same tension. If their cross-section area are in the ratio $1 : 4$ , then the respective wave velocities will be

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Answer:

Solution:

$v = \sqrt{\frac{T}{μ}} = \sqrt{\frac{T}{ρ A}}$

where, $ρ =$ density

$A =$ Area of cross-section

$μ = ρ A =$ mass of unit length

$\frac{v_{1}}{v_{2}} = \sqrt{\frac{A_{2}}{A_{1}}}$

$\frac{v_{1}}{v_{2}} = \sqrt{\frac{4}{1}}$

$\frac{v_{1}}{v_{2}} = \frac{2}{1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave on StringSubtopic:Equation/graph

⏱ 2mℹ️ Source: PYQ_2020

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