A travelling acoustic wave frequency 500 Hz is moving along the positive x -direction with a velocity of 300 ms − 1 . The phase difference between two points x 1 and x 2 is 6 0 ∘ . Then the minimu

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A travelling acoustic wave frequency 500 Hz is moving along the positive x -direction with a velocity of 300 ms − 1 . The phase difference between two points x 1 ​ and x 2 ​ is 6 0 ∘ . Then the minimum separation between the two points is

TestHub · Accepted Answer

By using the relation, v = v λ We have, λ = v V ​ = 500 300 ​ = 5 3 ​ m The phase difference, ϕ = λ 2 π ​ ( Δ x ) ⇒ 3 π ​ = 3 2 π × 5 ​ ( Δ x ) ⇒ Δ x = 10 1 ​ m = 10 cm

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