Physics - Vectors Question with Solution | TestHub

Given, $|\vec{A}|=7\sqrt{2}$ unit

$|\vec{B}|=14$ unit

Angle between the vectors, $\theta =60^{\circ }$

The scalar product of two vectors is given by $\vec{A}\cdot \vec{B}=|\vec{A}||\vec{B}|\cos \theta$

Substituting the given values:

$\vec{A}\cdot \vec{B}=(7\sqrt{2})(14)\cos (60^{\circ })$

$\vec{A}\cdot \vec{B}=98\sqrt{2}\times \frac{1}{2}$

$\vec{A}\cdot \vec{B}=49\sqrt{2}$

Answer: $49\sqrt{2}$