Vector A of magnitude 5 3 units, another vector B of magnitude of 10 units are inclined to each other at an angle of 3 0 ∘ . The magnitude of vector product of the two vectors is [ sin 3 0 ∘ = 2 1

Question

Vector A of magnitude 5 3 ​ units, another vector B of magnitude of 10 units are inclined to each other at an angle of 3 0 ∘ . The magnitude of vector product of the two vectors is [ sin 3 0 ∘ = 2 1 ​ ]

TestHub · Accepted Answer

The magnitude of the vector product of two vectors $A$ and $B$ is given by $∣ A \times B ∣ = ∣ A ∣∣ B ∣ sin θ$ .

Substituting the given values:

$∣ A \times B ∣ = (53) (10) sin 3 0^{\circ}$

$∣ A \times B ∣ = 503 \times \frac{1}{2}$

$∣ A \times B ∣ = 253$ units.

Answer: $253$ units

Physics - Vectors Question with Solution | TestHub

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