The magnitude of component of vector A = 3 i ^ + 4 j ^ along vector 2 i ^ + j ^ is α . Then find the value of 4 α 2 .

α = ( 3 i ^ + 4 j ^ ) ⋅ 5 2 i ^ + j ^ = 5 6 + 4 = 2 5 4 α 2 = 4 20 = 5 Answer: 5

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Physics - Vectors Question with Solution | TestHub

PhysicsVectorsComponentMedium2 minQB

PhysicsMediumnumerical

The magnitude of component of vector $A = 3 \hat{i} + 4 \hat{j}$ along vector $2 \hat{i} + \hat{j}$ is $α$ . Then find the value of $\frac{α ^{2}}{4}$ .

Answer:

5.00

Solution:

$α = (3 \hat{i} + 4 \hat{j}) \cdot \frac{2 i ^ + j ^}{5}$

$= \frac{6 + 4}{5} = 25$

$\frac{α ^{2}}{4} = \frac{20}{4} = 5$

Answer: 5

Subject:PhysicsTopic:VectorsSubtopic:Component

⏱ 2mℹ️ Source: QB

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