A vector in x - y plane makes an angle of 30 o with y -axis. The magnitude of y -component of vector is 2 3 . The magnitude of x -component of the vector will be :

The angle made by the vector on x axis is θ = 90 ° - 30 ° = 60 ° Let the vector be a → . It is given that a y = 2 3 ⇒ a sin 60 ° = 2 3 ⇒ a 3 2 = 2 3 ⇒ a = 4 x component is a x = a cos 60 ° ⇒ a x = 4 × 1 2 = 2

Physics - Vectors Question with Solution | TestHub

PhysicsVectorsAddition/SubtractionEasy2 minPYQ_2023

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A vector in $x - y$ plane makes an angle of $30^{o}$ with $y$ -axis. The magnitude of $y$ -component of vector is $2 \sqrt{3}$ . The magnitude of $x$ -component of the vector will be :

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Answer:

Solution:

The angle made by the vector on $x axis$ is
$θ = 90 ° - 30 ° = 60 °$
Let the vector be $\vec{a}$ .
It is given that
$a_{y} = 2 \sqrt{3} \Rightarrow a \sin 60 ° = 2 \sqrt{3} \Rightarrow \frac{a \sqrt{3}}{2} = 2 \sqrt{3} \Rightarrow a = 4$
$x$ component is $a_{x} = a \cos 60 ° \Rightarrow a_{x} = 4 \times \frac{1}{2} = 2$

Stream:JEESubject:PhysicsTopic:VectorsSubtopic:Addition/Subtraction

⏱ 2mℹ️ Source: PYQ_2023

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