Physics - Vectors Question with Solution | TestHub

After resolving forces in$xy-$direction, we get
Along$x$direction, net force;
$F_x=10\left[\cos {30}^o+\left(-\cos {45}^o\right)\right]=10\left(\frac{\sqrt{3}}{2}-\frac{1}{\sqrt{2}}\right)=1.59 \text{N}$
Along$y$direction, net force;
$F_y=10\left(\text{sin}{30}^o+10 \text{sin}{45}^o\right)$
$F_y=10\left(\frac{1}{2}+\frac{1}{\sqrt{2}}\right)$
$=12.07\mathrm{N}$
Thus forces in$x$and$y$direction are$1.59\text{N}$and$12.07\text{N}$respectively.