A unit vector is represented as ( 0.8 i ^ + b j ^ + 0.4 k ^ ) . Hence the value of 'b' must be

( 0.8 ) 2 + ( b ) 2 + ( 0.4 ) 2 = 1 0.64 + b 2 + 0.16 = 1 0.80 + b 2 = 1 0.80 + b 2 = 1 b 2 = 0.2 b = 0.2

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Physics - Vectors Question with Solution | TestHub

PhysicsVectorsMiscellaneousEasy2 minPYQ_2018

PhysicsEasysingle choice

A unit vector is represented as $(0.8 \hat{i} + b \hat{j} + 0.4 \hat{k})$ . Hence the value of 'b' must be

Options:

Answer:

Solution:

$\sqrt{{(0.8)}^{2} + {(b)}^{2} + {(0.4)}^{2}} = 1$
$\sqrt{0.64 + b^{2} + 0.16} = 1$
$\sqrt{0.80 + b^{2}} = 1$
$0.80 + b^{2} = 1$
$b^{2} = 0.2$
$b = \sqrt{0.2}$

Stream:MHT_CETSubject:PhysicsTopic:VectorsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2018

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