A particle is moving with a velocity v → = K y i ^ + x j ^ , where K is a constant. The general equation for its path is:

v → = K y i ^ + x j ^ v x = y = d x d t v y = x = d y d t d x d y = y x ∫ x d x = ∫ y d y x 2 2 = y 2 2 + C or y 2 = x 2 + c o n s t a n t

Physics - Vectors Question with Solution | TestHub

PhysicsVectorsMiscellaneousEasy2 minPYQ_2019

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A particle is moving with a velocity $\vec{v} = K (y \hat{i} + x \hat{j}),$ where $K$ is a constant.

The general equation for its path is:

Options:

Answer:

Solution:

$\vec{v} = K (y \hat{i} + x \hat{j})$

$v_{x} = y = \frac{d x}{d t}$

$v_{y} = x = \frac{d y}{d t}$

$\frac{d x}{d y} = \frac{y}{x}$

$\int x d x = \int y d y$

$\frac{x^{2}}{2} = \frac{y^{2}}{2} + C$

or $y^{2} = x^{2} + c o n s t a n t$

Stream:JEESubject:PhysicsTopic:VectorsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2019

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