Physics - Vectors Question with Solution | TestHub

The component of a vector $\vec{P}$ of magnitude $P$ making an angle $\theta$ with the x-axis, along the y-axis, is given by $P_y=P\sin \theta$. Given $P=10$ units and $\theta =60^{\circ }$.$P_y=10\sin (60^{\circ })=10\left(\frac{\sqrt{3}}{2}\right)=5\sqrt{3}$ units.