Show dimensionally whether the expression T = 2 π g l for the time period of a simple pendulum is dimensionally correct.

Start Free Mock LoginAlready registered? Login here

Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minQB

PhysicsEasysingle choice

Show dimensionally whether the expression $T = 2 π \frac{l}{g}$ for the time period of a simple pendulum is dimensionally correct.

Options:

Answer:

Solution:

RHS:
$\frac{[ L ]}{[ L T ^{- 2} ]} = [T^{2}] = [T]$
, which matches the dimensions of the time period on the LHS.
The expression is dimensionally correct.

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...