Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousMedium2 minPYQ_2020

PhysicsMediumsingle choice

Given, $B$ is magnetic field induction, and $μ_{0}$ is the magnetic permeability of vacuum. The dimension of $\frac{B^{2}}{2 μ_{0}}$ is:

Options:

Answer:

Solution:

Energy density in magnetic filed $= \frac{e n e r g y}{v o l u m e} = \frac{B^{2}}{2 μ_{0}}$
$= \frac{F o r c e \times d i s p l a c e m e n t}{{(d i s p l a c e m e n t)}^{3}} = \frac{M L T^{- 2} . L}{L^{3}} = {M L}^{- 1} T^{- 2}$

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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