The pressure of a gas is 1.5 × 1 0 5 N / ( m ) 2 . Express it in dyne/( cm ) 2 .

1.5 × 1 0 5 m 2 N = 1 0 4 1.5 × 1 0 5 × 1 0 5 cm 2 dyne = 1.5 × 1 0 6 cm 2 dyne .

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minQB

PhysicsEasynumerical

The pressure of a gas is $1.5 \times 1 0^{5} N / (m)^{2}$ . Express it in dyne/( cm $)^{2}$ .

Answer:

1500000.00

Solution:

$1.5 \times 1 0^{5} \frac{N}{m ^{2}}$
$= \frac{1.5 \times 1 0 ^{5} \times 1 0 ^{5}}{1 0 ^{4}} \frac{dyne}{cm ^{2}}$
$= 1.5 \times 1 0^{6} \frac{dyne}{cm ^{2}}$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

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