Physics - Unit & Dimension Question with Solution | TestHub

The dimensional formula is $[M^1{L}^{-2}{T}^{-2}]$.

Let's analyze the dimensions of each option:

A. Energy / Area: $[M{L}^2{T}^{-2}]/[L^2]=[M{T}^{-2}]$

B. Pressure: $[M{L}^{-1}{T}^{-2}]$

C. Force $\times$ length: $[ML{T}^{-2}]\times [L]=[M{L}^2{T}^{-2}]$

D. Pressure per unit length: $[M{L}^{-1}{T}^{-2}]/[L]=[M{L}^{-2}{T}^{-2}]$

Option D matches the given dimensional formula.