Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minQB

PhysicsEasysingle choice

The dimensional formula of Planck's constant is

Answer:

Solution:

From $E = h v : [h]$
$= \frac{[ M L ^{2} T ^{- 2} ]}{[ T ^{- 1} ]}$
$= [M L^{2} T^{- 1}]$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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