Physics - Unit & Dimension Question with Solution | TestHub

$\left(P+\frac{a}{V^2}\right)\left(V-b\right)=nRT$

Dimensions of $b$ should be equal to dimensions of $V$. Similarly, dimensions of $a$ will be equal to dimensions of $P{V}^2$.

Therefore, dimensions of $\left[\frac{a}{b}\right]=\left[\frac{P{V}^2}{V}\right]=\left[PV\right]$.