Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousMedium2 minPYQ_2021

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If $e$ is the electronic charge, $c$ is the speed of light in free space and $h$ is Planck's constant, the quantity $\frac{1}{4 π ε_{0}} \frac{{|e|}^{2}}{h c}$ has dimensions of :

Options:

Answer:

Solution:

$F = \frac{1}{4 π ϵ_{0}} \frac{e^{2}}{r^{2}}$

$E = \frac{h c}{λ}$

$[\frac{e^{2}}{4 π ε_{0}} \times \frac{1}{h c}] = \frac{F r^{2}}{E λ} = (M^{0} L^{0} T^{0})$

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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